{"id":558,"date":"2026-05-05T04:52:05","date_gmt":"2026-05-05T04:52:05","guid":{"rendered":"https:\/\/79.buffdemo.com\/index.php\/2026\/05\/05\/de-thi-thu-tot-nghiep-thpt-mon-toan-2024-2025-truong-thpt-chuyen-thai-binh\/"},"modified":"2026-05-05T07:25:48","modified_gmt":"2026-05-05T07:25:48","slug":"de-thi-thu-tot-nghiep-thpt-mon-toan-2024-2025-truong-thpt-chuyen-thai-binh","status":"publish","type":"post","link":"https:\/\/79.buffdemo.com\/index.php\/2026\/05\/05\/de-thi-thu-tot-nghiep-thpt-mon-toan-2024-2025-truong-thpt-chuyen-thai-binh\/","title":{"rendered":"\u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 Tr\u01b0\u1eddng THPT Chuy\u00ean Th\u00e1i B\u00ecnh"},"content":{"rendered":"

Th\u1eed s\u1ee9c v\u1edbi \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 Tr\u01b0\u1eddng THPT Chuy\u00ean Th\u00e1i B\u00ecnh<\/strong> s\u1ebd gi\u00fap c\u00e1c b\u1ea1n 12 l\u00e0m quen d\u1ea7n v\u1edbi c\u1ea5u tr\u00fac \u0111\u1ec1 thi ch\u00ednh th\u1ee9c c\u1ee7a b\u1ed9 v\u00e0 n\u1eafm \u0111\u01b0\u1ee3c ma tr\u1eadn \u0111\u1ec1 thi. T\u1eeb \u0111\u00f3 chu\u1ea9n b\u1ecb cho b\u1ea3n th\u00e2n l\u1ed9 tr\u00ecnh \u00f4n t\u1eadp hi\u1ec7u qu\u1ea3 v\u00e0 \u0111\u1ea1t th\u00e0nh t\u00edch cao nh\u1ea5t. H\u00e3y c\u00f9ng T\u00e0i Li\u1ec7u H\u1ecdc T\u1eadp<\/a> t\u00ecm hi\u1ec3u qua n\u1ed9i dung v\u00e0 \u00f4n thi ngay nh\u00e9!<\/p>\n

N\u1ed9i dung \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 Tr\u01b0\u1eddng THPT Chuy\u00ean Th\u00e1i B\u00ecnh<\/strong><\/h2>\n

N\u1ed9i dung \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 Tr\u01b0\u1eddng THPT Chuy\u00ean Th\u00e1i B\u00ecnh<\/strong> xoay quanh ki\u1ebfn th\u1ee9c tr\u1ecdng t\u00e2m m\u00f4n To\u00e1n 12 t\u1eeb x\u00e1c su\u1ea5t th\u1ed1ng k\u00ea, ph\u01b0\u01a1ng tr\u00ecnh, \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1, h\u00ecnh h\u1ecdc,\u2026 Qua \u0111\u00e2y, c\u00e1c b\u1ea1n h\u1ecdc sinh d\u1ec5 d\u00e0ng \u00f4n t\u1eadp l\u00fd thuy\u1ebft v\u00e0 c\u00e1c d\u1ea1ng b\u00e0i t\u1eadp trong \u0111\u1ec1 h\u01a1n. \u0110\u1ec3 chinh ph\u1ee5c \u0111\u01b0\u1ee3c tr\u1ecdng s\u1ed1 22 c\u00e2u h\u1ecfi v\u00e0 l\u00e0m b\u00e0i trong th\u1eddi gian 90 ph\u00fat, h\u00e3y xem qua ma tr\u1eadn \u0111\u1ec1 thi chi ti\u1ebft d\u01b0\u1edbi \u0111\u00e2y v\u00e0 th\u1eed s\u1ee9c ngay nh\u00e9:<\/p>\n

Ph\u1ea7n 1 \u2013 C\u00e2u tr\u1eafc nghi\u1ec7m nhi\u1ec1u ph\u01b0\u01a1ng \u00e1n l\u1ef1a ch\u1ecdn (12 c\u00e2u)<\/strong><\/p>\n

Th\u00ed sinh tr\u1ea3 l\u1eddi b\u1eb1ng c\u00e1ch ch\u1ecdn m\u1ed9t ph\u01b0\u01a1ng \u00e1n duy nh\u1ea5t trong 4 \u0111\u00e1p \u00e1n A, B, C, D. Tham kh\u1ea3o c\u00e2u h\u1ecfi sau:<\/p>\n

C\u00e2u 1:<\/strong> \u0110\u01b0\u1eddng cong \u1edf h\u00ecnh sau l\u00e0 \u0111\u1ed3 th\u1ecb c\u1ee7a m\u1ed9t trong b\u1ed1n h\u00e0m s\u1ed1 d\u01b0\u1edbi \u0111\u00e2y. H\u00e0m s\u1ed1 \u0111\u00f3 l\u00e0 h\u00e0m s\u1ed1 n\u00e0o?<\/p>\n

\"\"<\/p>\n

a) y = x\u00b3 – 3x + 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 b) y = x\u00b3 – 3x\u00b2 + 2 <\/p>\n

c) y = x\u00b3 – 6x + 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 d) y = -x\u00b3 + 3x\u00b2 + 2 <\/p>\n

C\u00e2u 2:<\/strong> Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh. \u0110\u1eb3ng th\u1ee9c n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u1eb3ng th\u1ee9c \u0111\u00fang?<\/p>\n

a) SA\u20d7 + SB\u20d7 + SC\u20d7 + SD\u20d7 = 0\u20d7 <\/p>\n

b) SA\u20d7 + SC\u20d7 = SB\u20d7 + SD\u20d7 <\/p>\n

c) SA\u20d7 + SB\u20d7 = SC\u20d7 + SD\u20d7 <\/p>\n

d) SB\u20d7 + SC\u20d7 = SA\u20d7 + SD\u20d7 <\/p>\n

Ph\u1ea7n 2 \u2013 C\u00e2u tr\u1eafc nghi\u1ec7m \u0111\u00fang sai ( 4 c\u00e2u)<\/strong><\/p>\n

\u0110\u1ec3 l\u00e0m quen v\u1edbi c\u00e1ch ra \u0111\u1ec1 thi t\u1ed1t nghi\u1ec7p thpt m\u00f4n to\u00e1n<\/a> ch\u00ednh th\u1ee9c. H\u00e3y c\u00f9ng xem v\u00e0 gi\u1ea3i nhanh c\u00e1c c\u00e2u h\u1ecfi sau:<\/p>\n

C\u00e2u 1:<\/strong> Cho h\u00e0m s\u1ed1 y = f(x) = (ax + b)\/(cx + 1) , v\u1edbi a, b, c in mathbbR , c\u00f3 \u0111\u1ed3 th\u1ecb l\u00e0 h\u00ecnh b\u00ean.
\nC\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00fang hay sai?<\/p>\n

\"\"<\/p>\n

a) \u0110\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 f'(x) < 0 ; forall x in mathbbR setminus -1\/c <\/p>\n

b) H\u00e0m s\u1ed1 y = f(x) ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng (1; +\u221e) v\u00e0 \u0111\u1ed3ng bi\u1ebfn tr\u00ean kho\u1ea3ng (-\u221e; 1) <\/p>\n

c) \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x) c\u00f3 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn \u0111\u1ee9ng l\u00e0 x = 1 v\u00e0 \u0111\u01b0\u1eddng ti\u1ec7m c\u1eadn ngang l\u00e0 y = -1 <\/p>\n

d) T\u1ed5ng a + b + c = 5 <\/p>\n

C\u00e2u 2:<\/strong> Cho h\u00e0m s\u1ed1 y = f(x) = ax\u00b3 + bx\u00b2 + cx + d c\u00f3 b\u1ea3ng bi\u1ebfn thi\u00ean nh\u01b0 h\u00ecnh v\u1ebd.<\/p>\n

\"\"
\nC\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00fang hay sai?<\/p>\n

a) H\u00e0m s\u1ed1 y = f(x) c\u00f3 hai \u0111i\u1ec3m c\u1ef1c tr\u1ecb.<\/p>\n

b) H\u00e0m s\u1ed1 y = f(x) c\u00f3 gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t b\u1eb1ng 2 v\u00e0 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t b\u1eb1ng -2.<\/p>\n

c) H\u00e0m s\u1ed1 g(x) = 3x – f(x) ngh\u1ecbch bi\u1ebfn tr\u00ean kho\u1ea3ng (0; 2) <\/p>\n

d) \u0110\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y = f(x) \u0111i qua \u0111i\u1ec3m A(-1; -2) <\/p>\n

Ph\u1ea7n 3 \u2013 C\u00e2u tr\u1eafc nghi\u1ec7m tr\u1ea3 l\u1eddi ng\u1eafn (6 c\u00e2u)
\n<\/strong><\/p>\n

Th\u00ed sinh tr\u1ea3 l\u1eddi c\u00e1c c\u00e2u h\u1ecfi sau v\u00e0 m\u1ed7i \u00f4 tr\u1ea3 l\u1eddi t\u01b0\u01a1ng \u0111\u01b0\u01a1ng theo h\u01b0\u1edbng d\u1eabn c\u1ee7a phi\u1ebfu tr\u1ea3 l\u1eddi:<\/p>\n

C\u00e2u 1.<\/strong> M\u1ed9t v\u1eadt chuy\u1ec3n \u0111\u1ed9ng tr\u00ean \u0111\u01b0\u1eddng th\u1eb3ng c\u00f3 qu\u00e3ng \u0111\u01b0\u1eddng \u0111i chuy\u1ec3n trong kho\u1ea3ng th\u1eddi gian t (gi\u00e2y) \u0111\u01b0\u1ee3c cho b\u1edfi ph\u01b0\u01a1ng tr\u00ecnh: s(t) = 1\/3t\u00b3 + 6t\u00b2 (m), v\u1edbi 0 \u2264 t \u2264 12
\nT\u00ednh t\u1eeb khi b\u1eaft \u0111\u1ea7u di chuy\u1ec3n \u0111\u1ebfn th\u1eddi \u0111i\u1ec3m v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt \u0111\u1ea1t gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t th\u00ec v\u1eadt \u0111i chuy\u1ec3n \u0111\u01b0\u1ee3c qu\u00e3ng \u0111\u01b0\u1eddng d\u00e0i bao nhi\u00eau m\u00e9t (l\u00e0m tr\u00f2n \u0111\u1ebfn h\u00e0ng \u0111\u01a1n v\u1ecb)?<\/p>\n

C\u00e2u 2.<\/strong> Cho h\u00e0m s\u1ed1 y = (ax\u00b2 + bx + c)\/(x + d) c\u00f3 \u0111\u1ed3 th\u1ecb nh\u01b0 h\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y. T\u00ednh a + b + c + d .<\/p>\n

\"\"<\/p>\n

T\u1ea3i \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 Tr\u01b0\u1eddng THPT Chuy\u00ean Th\u00e1i B\u00ecnh<\/strong><\/h2>\n

C\u00e1c b\u1ea1n h\u1ecdc sinh n\u00ean luy\u1ec7n t\u1eadp th\u01b0\u1eddng xuy\u00ean v\u1edbi nhi\u1ec1u \u0111\u1ec1 thi th\u1eed kh\u00e1c nhau \u0111\u1ec3 n\u00e2ng cao kh\u1ea3 n\u0103ng t\u01b0 duy logic v\u00e0 t\u01b0 duy gi\u1ea3i \u0111\u1ec1. H\u00e3y t\u1ea3i \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 Tr\u01b0\u1eddng THPT Chuy\u00ean Th\u00e1i B\u00ecnh<\/strong> qua \u0111\u01b0\u1eddng link d\u01b0\u1edbi \u0111\u00e2y v\u00e0 th\u1eed s\u1ee9c ngay n\u00e0o. V\u1edbi \u0111\u00e1p \u00e1n chi ti\u1ebft k\u00e8m theo, sau khi l\u00e0m xong b\u1ea1n d\u1ec5 d\u00e0ng tra c\u1ee9u v\u00e0 hi\u1ec3u \u0111\u01b0\u1ee3c v\u1ea5n \u0111\u1ec1 c\u00e1c c\u00e2u \u0111\u00e3 l\u00e0m sai. Ch\u00fac b\u1ea1n \u0111\u1ea1t k\u1ebft qu\u1ea3 cao nh\u1ea5t nh\u00e9!<\/p>\n