{"id":502,"date":"2026-05-05T04:49:11","date_gmt":"2026-05-05T04:49:11","guid":{"rendered":"https:\/\/79.buffdemo.com\/index.php\/2026\/05\/05\/de-thi-thu-tot-nghiep-thpt-mon-toan-2024-2025-so-gd-dt-ba-ria-vung-tau\/"},"modified":"2026-05-05T07:22:25","modified_gmt":"2026-05-05T07:22:25","slug":"de-thi-thu-tot-nghiep-thpt-mon-toan-2024-2025-so-gd-dt-ba-ria-vung-tau","status":"publish","type":"post","link":"https:\/\/79.buffdemo.com\/index.php\/2026\/05\/05\/de-thi-thu-tot-nghiep-thpt-mon-toan-2024-2025-so-gd-dt-ba-ria-vung-tau\/","title":{"rendered":"\u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 S\u1edf GD & \u0110T B\u00e0 R\u1ecba V\u0169ng T\u00e0u"},"content":{"rendered":"

\u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 S\u1edf GD & \u0110T B\u00e0 R\u1ecba V\u0169ng T\u00e0u<\/strong> l\u00e0 t\u00e0i li\u1ec7u \u00f4n t\u1eadp quan tr\u1ecdng d\u00e0nh cho h\u1ecdc sinh 12 r\u00e8n luy\u1ec7n k\u0129 n\u0103ng v\u00e0 chu\u1ea9n b\u1ecb qu\u00e1 tr\u00ecnh \u00f4n thi. T\u00e0i li\u1ec7u v\u1edbi \u0111a d\u1ea1ng c\u00e2u h\u1ecfi t\u1eeb nh\u1eadn bi\u1ebft \u0111\u1ebfn v\u1eadn d\u1ee5ng, \u0111\u1eb7c bi\u1ec7t \u0111\u1ec1 c\u00f2n k\u00e8m \u0111\u00e1p \u00e1n v\u00e0 c\u00e1ch gi\u1ea3i chi ti\u1ebft \u1edf cu\u1ed1i, h\u1ed7 tr\u1ee3 c\u00e1c b\u1ea1n trong qu\u00e1 tr\u00ecnh gi\u1ea3i \u0111\u1ec1 v\u00e0 s\u1eeda b\u00e0i. Xem qua n\u1ed9i dung c\u1ee7a \u0111\u1ec1 thi c\u00f9ng v\u1edbi T\u00e0i li\u1ec7u \u00d4n Thi<\/a> n\u00e0o.<\/p>\n

N\u1ed9i dung \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 S\u1edf GD & \u0110T B\u00e0 R\u1ecba V\u0169ng T\u00e0u<\/strong><\/h2>\n

T\u01b0\u01a1ng t\u1ef1 v\u1edbi c\u00e1c \u0111\u1ec1 thi thpt to\u00e1n<\/a> kh\u00e1c, \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 S\u1edf GD & \u0110T B\u00e0 R\u1ecba V\u0169ng T\u00e0u<\/strong> \u0111\u01b0\u1ee3c bi\u00ean so\u1ea1n kh\u00e1 chu\u1ea9n v\u1edbi format m\u00e0 b\u1ed9 \u0111\u00e3 \u0111\u01b0a ra. N\u1ed9i dung c\u1ee7a \u0111\u1ec1 thi c\u00f3 \u0111\u1ed9 ph\u00e2n c\u1ea5p r\u00f5 r\u00e0ng, nh\u1eb1m \u0111\u00e1nh gi\u00e1 ch\u00ednh x\u00e1c \u0111\u01b0\u1ee3c n\u0103ng l\u1ef1c c\u1ee7a th\u00ed sinh.<\/p>\n

Ph\u1ea7n 1 \u2013 C\u00e2u h\u1ecfi tr\u1eafc nghi\u1ec7m nhi\u1ec1u ph\u01b0\u01a1ng \u00e1n l\u1ef1a ch\u1ecdn<\/strong><\/span><\/p>\n

M\u1eddi qu\u00fd th\u1ea7y c\u00f4 v\u00e0 c\u00e1c b\u1ea1n h\u1ecdc sinh c\u00f9ng xem qua c\u00e1c c\u00e2u h\u1ecfi sau \u0111\u1ec3 c\u00f3 k\u1ebf ho\u1ea1ch \u00f4n t\u1eadp hi\u1ec7u qu\u1ea3 nh\u1ea5t cho m\u00ecnh:<\/p>\n

C\u00e2u 1<\/strong>: M\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y sai?<\/p>\n

\\begin{align*}
\n\\text{A. } & \\int a^x dx = \\frac{a^x}{\\ln a} + C, \\quad (0 < a \\ne 1). \\\\
\n\\text{B. } & \\int \\sin x\\, dx = \\cos x + C. \\\\
\n\\text{C. } & \\int \\frac{1}{x} dx = \\ln |x| + C, \\quad x \\ne 0. \\\\
\n\\text{D. } & \\int e^x dx = e^x + C.
\n\\end{align*}<\/p>\n

C\u00e2u 2<\/strong>: Cho h\u00e0m s\u1ed1 f(x) li\u00ean t\u1ee5c tr\u00ean mathbbR v\u00e0 F(x) l\u00e0 nguy\u00ean h\u00e0m c\u1ee7a f(x) , bi\u1ebft int\u2080\u2079 f(x) dx = 9 v\u00e0 F(0) = 3. T\u00ednh F(9) .<\/p>\n

A.\u00a0 & F(9) = -12.\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 & F(9) = 6.\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 & F(9) = 12.\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 & F(9) = -6.<\/p>\n

Ph\u1ea7n 2 \u2013 C\u00e2u h\u1ecfi tr\u1eafc nghi\u1ec7m \u0111\u00fang sai<\/strong><\/span><\/p>\n

M\u1ed7i \u0111\u1ec1 c\u00f3 t\u1ea5t c\u1ea3 4 c\u00e2u h\u1ecfi v\u1ec1 c\u00e1c ki\u1ebfn th\u1ee9c c\u01a1 b\u1ea3n \u0111\u1ebfn n\u00e2ng cao. K\u00e8m theo l\u00e0 c\u00e1c c\u00e2u tr\u1ea3 l\u1eddi s\u1eb5n c\u00f3, th\u00ed sinh ch\u1ec9 c\u1ea7n ch\u1ecdn m\u1ec7nh \u0111\u1ec1 \u0110\u00daNG\/SAI<\/strong> cho m\u1ed7i \u0111\u00e1p \u00e1n. V\u00ed d\u1ee5 nh\u01b0:<\/p>\n

C\u00e2u 1: Cho h\u00e0m s\u1ed1 f(x) = 1\/2x\u00b2 + x – 6ln(x+2) <\/p>\n

a) \u0110\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 l\u00e0 f'(x) = x + 1 – 6\/x+2 .<\/p>\n

b) Tr\u00ean \u0111o\u1ea1n [-1; 2] , ph\u01b0\u01a1ng tr\u00ecnh f'(x) = 0 c\u00f3 hai nghi\u1ec7m ph\u00e2n bi\u1ec7t.<\/p>\n

c) f(-1) = -1\/2 v\u00e0 f(2) = 4 – 12ln 2 .<\/p>\n

d) Gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t c\u1ee7a f(x) tr\u00ean \u0111o\u1ea1n [-1; 2] l\u1edbn h\u01a1n -5 .<\/p>\n

C\u00e2u 2<\/strong>: M\u1ed9t ch\u1ea5t \u0111i\u1ec3m A xu\u1ea5t ph\u00e1t t\u1eeb O , chuy\u1ec3n \u0111\u1ed9ng th\u1eb3ng v\u1edbi v\u1eadn t\u1ed1c bi\u1ebfn thi\u00ean theo th\u1eddi gian b\u1edfi quy lu\u1eadt v(t) = (100t\u00b2)\/(13t\u00b2 + 30) (m\/s), trong \u0111\u00f3 t (gi\u00e2y) l\u00e0 kho\u1ea3ng th\u1eddi gian t\u00ednh t\u1eeb l\u00fac A b\u1eaft \u0111\u1ea7u chuy\u1ec3n \u0111\u1ed9ng. T\u1eeb tr\u1ea1ng th\u00e1i ngh\u1ec9, m\u1ed9t ch\u1ea5t \u0111i\u1ec3m B c\u0169ng xu\u1ea5t ph\u00e1t t\u1eeb O , chuy\u1ec3n \u0111\u1ed9ng th\u1eb3ng c\u00f9ng h\u01b0\u1edbng v\u1edbi A nh\u01b0ng ch\u1eadm h\u01a1n 10 gi\u00e2y so v\u1edbi A , v\u00e0 c\u00f3 gia t\u1ed1c a (m\/s\u00b2) ( a l\u00e0 h\u1eb1ng s\u1ed1). Sau khi B xu\u1ea5t ph\u00e1t \u0111\u01b0\u1ee3c 15 gi\u00e2y th\u00ec \u0111u\u1ed5i k\u1ecbp A .<\/p>\n

a) V\u1eadn t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m B l\u00e0 v_B(t) = at , trong \u0111\u00f3 t l\u00e0 th\u1eddi gian t\u00ednh t\u1eeb l\u00fac B b\u1eaft \u0111\u1ea7u chuy\u1ec3n \u0111\u1ed9ng.<\/p>\n

b) Qu\u00e3ng \u0111\u01b0\u1eddng ch\u1ea5t \u0111i\u1ec3m A \u0111i \u0111\u01b0\u1ee3c trong 10 gi\u00e2y \u0111\u1ea7u l\u00e0 25 m .<\/p>\n

c) Qu\u00e3ng \u0111\u01b0\u1eddng ch\u1ea5t \u0111i\u1ec3m B \u0111i \u0111\u01b0\u1ee3c trong 15 gi\u00e2y l\u00e0 225a\/2 m.\n<\/p>\n

d) V\u1eadn t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m B t\u1ea1i th\u1eddi \u0111i\u1ec3m \u0111u\u1ed5i k\u1ecbp A l\u00e0 25 m\/s .<\/p>\n

Ph\u1ea7n 3 \u2013 C\u00e2u tr\u1eafc nghi\u1ec7m tr\u1ea3 l\u1eddi ng\u1eafn
\n<\/strong><\/span>
\nTr\u00edch m\u1ed9t s\u1ed1 c\u00e2u h\u1ecfi trong \u0111\u1ec1 thi th\u1eed:<\/p>\n

C\u00e2u 1<\/strong>: Cho h\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c \u0111\u1ec1u SABCD , c\u00f3 c\u1ea1nh \u0111\u00e1y b\u1eb1ng 2, c\u1ea1nh b\u00ean b\u1eb1ng 3. T\u00ednh kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111\u01b0\u1eddng th\u1eb3ng AB v\u00e0 SD (k\u1ebft qu\u1ea3 l\u00e0m tr\u00f2n hai ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n).<\/p>\n

C\u00e2u 2<\/strong>: Tr\u01b0\u1eddng THPT A t\u1ed5 ch\u1ee9c chuy\u1ebfn \u0111i v\u1ec1 ngu\u1ed3n cho h\u1ecdc sinh tham quan 4 \u0111\u1ecba \u0111i\u1ec3m A, B, C, D . Th\u1eddi gian (\u0111\u01a1n v\u1ecb: ph\u00fat) di chuy\u1ec3n qua l\u1ea1i gi\u1eefa c\u00e1c \u0111i\u1ec3m tham quan \u0111\u01b0\u1ee3c m\u00f4 t\u1ea3 \u1edf h\u00ecnh b\u00ean. \u0110o\u00e0n h\u1ecdc sinh c\u1ee7a tr\u01b0\u1eddng s\u1ebd tham quan m\u1ed9t \u0111\u1ecba \u0111i\u1ec3m n\u00e0o \u0111\u00f3 \u0111\u1ea7u ti\u00ean, r\u1ed3i \u0111i qua t\u1ea5t c\u1ea3 c\u00e1c \u0111\u1ecba \u0111i\u1ec3m c\u00f2n l\u1ea1i, m\u1ed7i khi \u0111\u00e3 tham quan \u0111\u1ecba \u0111i\u1ec3m n\u00e0o r\u1ed3i th\u00ec s\u1ebd kh\u00f4ng quay l\u1ea1i \u0111\u00f3 n\u1eefa nh\u01b0ng ph\u1ea3i v\u1ec1 \u0111\u1ecba \u0111i\u1ec3m ban \u0111\u1ea7u \u0111\u1ec3 tr\u1edf v\u1ec1. H\u1ecfi t\u1ed5ng th\u1eddi gian tham quan c\u00e1c \u0111\u1ecba \u0111i\u1ec3m th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n tr\u00ean nh\u1eadn gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t l\u00e0 bao nhi\u00eau?<\/p>\n

\"\"<\/p>\n

T\u1ea3i \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 S\u1edf GD & \u0110T B\u00e0 R\u1ecba V\u0169ng T\u00e0u<\/strong><\/h2>\n

C\u00e1c b\u1ea1n h\u1ecdc sinh 12 v\u00e0 th\u1ea7y c\u00f4 \u0111\u1eebng b\u1ecf l\u1ee1 \u0110\u1ec1 thi th\u1eed t\u1ed1t nghi\u1ec7p THPT m\u00f4n To\u00e1n 2024 \u2013 2025 S\u1edf GD & \u0110T B\u00e0 R\u1ecba V\u0169ng T\u00e0u<\/strong>. B\u1edfi \u0111\u00e2y l\u00e0 \u0111\u1ec1 thi c\u00f3 c\u1ea5u tr\u00fac b\u00e1m s\u00e1t v\u1edbi \u0111\u1ec1 thi th\u1eadt, c\u00f3 \u0111\u00e1p \u00e1n chi ti\u1ebft gi\u00fap b\u1ea1n t\u1ef1 \u0111\u00e1nh gi\u00e1 v\u00e0 c\u1ee7ng c\u1ed1 ki\u1ebfn th\u1ee9c hi\u1ec7u qu\u1ea3. H\u00e3y t\u1ea3i ngay \u0111\u1ec1 thi qua \u0111\u01b0\u1eddng link d\u01b0\u1edbi \u0111\u00e2y v\u00e0 b\u1eaft tay v\u00e0o luy\u1ec7n t\u1eadp ngay h\u00f4m nay nh\u00e9!<\/p>\n